A result on modular forms in characteristic p - Semantic Scholar

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The Hasse invariant A c R is defined modularly as olo follows. Given (E,~,(~) over B, let r i c HI(E,OE ) be the basis. ] dual to ~ c H0(E,CE/B). The p'th power ...
Ka- I

A RESULT

ON MODULAR FORMS IN C H A R A C T E R I S T I C Nicholas

p

M. Katz

ABSTRACT e = q ~d

The action of the derivation modular

forms in characteristic

in the S e r r e / S w i n n e r t o n - D y e r this note, we extend

the basic

results

P > 5 and level one,

prime-to-p

level.

!.

of modular forms

We fix an a l g e b r a i c a l l y p > 0, an integer of u n i t y

~ ~ K.

K-algebras

N > 3

this action, p

in characteristic closed

prime

N

about

to a r b i t r a r y

to

field p,

The moduli problem

with level

represented

is one of the fundamental

theory of mod p modular forms.

known for

Review

p

on the q-expansions

structure

tools In

already

and a r b i t r a r y

p

K

of characteristic

and a primitive

"elliptic ~

of

curves

N'th root E

of determinant

over {"

is

by (Euniv i ~univ)

MN with

MN

a smooth affine

the invertible

sheaf on

irreducible

curve over

MN I = ~, flEuniv/M N

the graded level

N

ring

R~

modular forms over O k~

nowhere-vanishing

'

of (not n e c e s s a r i l y h o l o m o r p h i c

Given a K - a l g e b r a

In terms of

K.

B,

invariant

K

at the cusps)

is

H O ( M N , @ f k) a test object differential

(E,~) ~

on

over E,

B,

and a

any element

54

Ka-2

f e RN

(not n e c e s s a r i l y homogeneous)

and

is determined

f

Over

by all of its values

B = K((ql/N)),

"canonical"

differential

"is"

from

aso

dt/t

~m ).

of determinant

K((ql/n)),

we have C0can

(cf.

e B,

[2]).

(viewing Tare(q)

on Tare(q),

f(E,~,~)

the Tate curve Tare(q)

By evaluating

~

we obtain

corresponding

has a value

as

with

~m/q ~,

at the level

N

~can

structures

all of w h i c h are defined

the q-expansions

of elements

its

over

f e R N at the

cusps: dfn fm0(q)

A homogeneous k

f e R kN

element

and to be a cusp q I/NK[[ql/N]] R~,holo

of

follows. dual to

RN,

invariant

of itself.

A(E,~,~)

defines

B,

K[[ql/N]],

lie in a subring ideal in

of

RN,holo.

is defined m o d u l a r l y as

let

ri c HI(E,OE )

The p'th power e n d o m o r p h i s m

= A(E,~,~)-,~

HI(E,OE ),

be the basis x -~ x p

w h i c h must carry

N

in

of r;

to

HI(E,OE ),

w h i c h is the value of

of the Hasse

A o(q ) = l For each level

olo

is said

So we can write

c B,

the q-expansions

q-expansion

over

an e n d o r m o r p h i s m

~P for some

lie in

forms constitute

A c R

by its weight

f c R kN

and the cusp forms are a graded

(E,~,(~) ] ~ c H0(E,CE/B).

a multiple

A form

form if all of its q-expansions

Given

induces

determined

if all of its q-expansions

The holomorphic

The Hasse

All

is u n i q u e l y

and by any one of its q-expansions.

to be holomorphic

OE

f ( T a t e ( q ) , ~ c a n , ~ 0) e K((ql/N))

in

invariant

K((q~/N))

structure

so

A

on

(E,~,~).

are i d e n t i c a l l y

]:

for each s o. on Tare(q),

the c o r r e s p o n d i n g

ring h o m o m o r p h i s m s

whose kernels are p r e c i s e l y

the principal

ideals

(A-I)R~

and

55

(A-l)R~,holo

r e s p e c t i v e l y ([4], k f ~ RN

A form

not d i v i s i b l e b y f'

k~ RN

q-expansion I!.

A

that

in

f

R~,

([4],

or equivalently,

which,

k

if it is

if there is no form

at some cusp, has

the same

does.

S t a t m e n t of the theorem, The f o l l o w i n g

[5]).

is said to be of exact f i l t r a t i o n

k' ( k

with

~-3

and its c o r o l l a r i e s

theorem is due to Serre and S w i n n e r t o n - D y e r

[5]) in c h a r a c t e r i s t i c

P > 5,

and level

N = I.

Theorem. (I)

There exists a d e r i v a t i o n

increases degrees by is

q~

d

p + I,

which

effect u p o n each q - e x p a n s i o n

:

(A0f)

(q) = q d_ (fso(q)) for each So

(2)

divide

and whose

A 0 : R ~ ~ RN+P+~

k,

particular (3)

If

then

f

dq

R kN

c

A0f

has exact f i l t r a t i o n has exact f i l t r a t i o n

k,

S O

and

k + p +

p

~,

does not and in

A 0 f ~ O. If

f c R~ k

and

A 0 f = 0,

then

f = gP

for a unique

k g c RN . Some C o r o l l a r i e s (])

The o p e r a t o r

A0

to the ideal of cusp forms. (2)

If

I ~ k ~ p - 2, then

g

f then

injective. (4)

If

the subring of h o l o m o r p h i c

f

has exact f i l t r a t i o n of w e i g h t

] ~ k ~ p - 2,

f

the map

(For if

is h o l o m o r p h i c

g

then

g

vanishes

f

(For if hence

of w e i g h t

has exact f i l t r a t i o n

at one cusp,

f = Ag, g = 0.) is

the theorem.)

is n o n - z e r o and h o l o m o r p h i c then

constant; as

k.

k ~ Rk+P+1 A 0 :RN,holo N,holo

and vanishes at some cusp, f = Ag,

of weight

k - (p-l) ~ O,

(This follows from (2) above and If

forms

(Look at q - e x p a n s i o n s . )

is n o n - z e r o and holomorphic,

is h o l o m o r p h i c (3)

maps

p - l, p - ~.

of w e i g h t O, hence

it must be zero.)

Ka-4

56

(5)

(determination

of

Ker(Ae)).

then we can uniquely write

f = Ar.g p

f ~ R kN

If with

0 ~ r < p - I,

r + k ~ O(mod p), and g ~ R~ with pf + r(p-]) = k. by induction If

r ~ O,

the

theorem

on

r,

then

the case

k @ O(p),

f = Ah

for

but

resp.

invariant

unicity !I!.

of

above,

Aef = 0.

we h a v e

if

f

(This is proven

(3) of the theorem.

Hence by part (2) of Because

Aeh = O,

and

is holomorphic

by a subgroup of

and

h

(resp.

SL2(Z/NZ)),

f

h

has lower r.) a cusp form,

so i s

g

(by

g).

Beginning

of the proof:

The a b s o l u t e

Frobenius

F-linear back

In (5)

being part

k+]-p h ~ RN

some

h a v e t h e same q - e x p a n s i o n s , (6)

r = 0

Aef = 0,

has

endomorphism of

(F) Euniv

of

its finite flat rank

endomorphism

p

obtained

subgroup

is the relative Frobenius 1

F

of

MN

scheme

induces

as follows.

by dividing

an

The p u l l -

Euniv

Ker Fr

part

by

where

~(F) > ~univ

Fr:Euniv

*

e a n d A~, a n d p r o v i n g

H 1 (E /M ~ DR u n i v " N / ' is

Euniv

defining

morphism.

The desired map is

Fr

(F)

F r : HDR(Euniv /MN)

>4R(Euniv/MN)

~ R ( E u n i v / M N ) (F) Lemma of

].

The image

U

of

Fr

is a locally free submodule

H~(Eunl~n"v/M-)N

of rank one, with the quotient H~R(Euniv/MN)/U ,Hasse locally free of rank one. The open set M N C M N where A is invertible filtration, Proof.

is the largest open set over which i.e., where

~@U

Because F~ k i l l s

through the quotient

>

U

splits

R(Euniv/MN).

HO(Euniv , ~Euniv/MN )(F)

H](Euniv,O) (F),

inclusion map in the "conjugate

the Hodge

where it induces

filtration"

it

factors

the

short exact sequence

(1)

Ke-~

57

(cf [~], 2.3) 0 -->

HI

(F)

This proves

filtration,

~, rl

H~R

DR = ] ~,

--> HO(Euniv ,

the first part of the lemma.

the Hodge of

nl

Fr -->4R(Euniv/MN)

(Euniv,@)

Then

to the Hodge

~

and so the matrix

To see where

we can w o r k locally on

adapted

projects of

Fr

M N.

filtration,

to a basis

on

*

R

4

Euniv/MN)

of

U

- - > O.

splits

Choose a basis

and satisfying HI(E,OE )

is (remembering

dual

to

Fr(~ (

~) )

*

= 0)

(0 A where by

A

is the value of the Hasse

Be + A~,

span

H~R

and the condition

is p r e c i s e l y

Remark. and

that

According B

A

invariant.

that

e

and

Thus Be + A~

zero.

This will be crucial later.

(Compare [ 2 ] , A1.4.)

w h i c h for each integer

Over

e

M~a s s e ,

k > I

of

RN[I/A]

induces a d e c o m p o s i t i o n

. . . ~ U®k

The G a u s s - M a n i n connection ]

k > I

the K o d a i r a - S p e n c e r

I

a connection

isomorphism

£

as follows.

we have the d e c o m p o s i t i o n

Symmk~R ~ _m®k(~) (e®k-1 ( ~ ) (~U) _

Using

the func-

w h i c h occur in the above m a t r i x have no common

We can now define a d e r i v a t i o n

for each

Q.E.D.

to the first part of the lemma,

A

is spanned together

be invertible.

tions

induces,

U

~

([2], A.].3.]7)

HN/K

Ka-

58

6

we can define a mapping of sheaves ®k

®k+ 2

as the composite

> Sym:L

=

--

DR

(~ --

Iil

"'"

f~MR

KS

-

Pr 1 __} ~®k+ 2

Passing to global sections over

MHasse -N '

we obtain, for

k > I,

a map 0,~Hasse :H ~ N "--

e "

Lemma 2. Proof. co®2

over

Hasse ,,@k+2 ) > H0(mN ,m

"

The effect of

@

upon q-expansions is

d

qT@"

Consider Tate(q) with its canonical differential k((ql/N))

Under the Kodaira-Spencer isomorphism,

can

®can

corresponds

q ~d

.

C

v(q ~ ) ( ~ c a n ) .

~O,~Hasse~ _.~ , _®k),

on (Tate(q), some ~0)

v(f

dq/q,

the dual derivation to which is

By the explicit calculations of ([2], A.2.2.7),

spanned by f

to

U

Thus given an element

its local expression as a section of is

is

_

®k

f 0(q).~ @kcan. Thus ®k

dq q

®k

®2 ~can

®k ) V(q ~ - - ~ )f~0 ((q)'~can) c~0 (q)'ecan = d (q)'~can) : v(q T4)(f%

d d ®k+ 2 ® k + I .V( q -d-~)(~can) ' : q d-q (f~0 (q))" ~can + k~f~0(q)" can Because

~ (q ~q)

(~can)

lies in

U,

it follows from

59 the d e f i n i t i o n of

e

Ka-7 d (ef)~o(q) = q d-q (f~0 (q))

that we have

.

Q.E.D. L e m m a 3.

For

k ~

],

k Ae:R N

there is a unique map

~k+p+1 > mN

such that the d i a g r a m b e l o w commutes

HO( 4 a s s e , )~_ k

9_~_> re'O". Hassek~N ,£®k+2~

U RNk = H0(MN, @k) Proof. basis of

A g a i n we w o r k l o c a l l y on

by the K o d a i r a - S p e n c e r DerNN/K

= HO(MN,fk+P+?) > ~k+p+l ~N

A0

£, ~ the local basis

dual to

~,

M N.

I

of

~MN/K

isomorphism, and

×A > n"O'kmN~asse,~®k+ p+ ] )

D

~' = V ( D ) @

Let

@

be a local

corresponding

to

the local basis ~ ~R"

Then

of

< @ ' ~ ' > D R = I,

(this c h a r a c t e r i z e s D), so that @ and m' form a basis of ] HDR , adapted to the Hodge filtration, in terms of w h i c h the m a t r i x of

Fr

is

0B) (0 A with

A = A(E,e).

w h i c h is dual to satisfies

Let e.

u e U Then

< e ' ~ ' > D R = I,

u

be the basis of

U

is p r o p o r t i o n a l

to

~asse MN

over

Be + Ae',

and

k f e RN,

and

so that B

l

u = K ~ + e In terms of all this, we will compute

9f

show that it has at worst a single power of Locally,

f

is the section

f]-@

®k

of

~

A ®k

,

for

in its denominator. with

fl

v(f~ ~k) = v(D)(f1~®k).~ = V(D)(flco ®k) .@®2 ®k+ 2 ®k+ = D(f] ).co + kf1@

1 .co,

B = D ( f I) ®k+2 + kflco®k+1(u _ K d~)

holomorphic.

60 Ka-8

-kf

: (D(fl) Thus

of

from the d e f i n i t i o n

~(f)

B ®k+2 • K)

1 of

e

it follows

We can now conclude

RN

But as (e.g.,

R~ A),

Conclusion

A~(f'aPr) AP r for

of the proof:

f e R kN

(as section of

Rather

Locally Ok

,

R~

of positive of positive

extends u n i q u e l y

for

to all of

r >> 0

k

for

A

in

and

R~,

f e RN

A~(f)

This means

that

that at some zero of ®k)

than

must be invertible

A

f

A,

does

[3] that

A

at some zero

we will not make use of this fact.) ~

of

~.

Then

f

becomes

is given by

~k) = (kD(fl)_kBfl) k

is not divisible

is invertible

at all zeros of

]).

x s MN

Thus if

f

we pick a basis

A~(f~Suppose now that

i.e.,

k.

(In fact, we know by Igusa

so in fact

MN,

(2) and (3)

(as section of

surprisingly,

on

Parts

has exact f i l t r a t i o n

®p-l).

has simple zeros,

f].~

of

Ae(f)

has a lower order zero

A.

Ae

= (AD(fl)-kfiB)~ ®k+p+1

is not divisible by

of

on elements

Up

valid.

Suppose

f

(1) of the theorem.

formula

The local expression

Ae(f)

Q.E.D.

has units which are h o m o g e n e o u s

Aef

IV.

A

the d e r i v a t i o n

by the explicit

remains

that the local expression

- kf I ~--) ® k + 2

the proof of Part

to now, we have only defined

degree

"u

is 0(f) = (D(f~)

degree.

®!