Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2013, Article ID 918513, 7 pages http://dx.doi.org/10.1155/2013/918513
Research Article Asymptotic Estimates for Second Kind Generalized Stirling Numbers Cristina B. Corcino1 and Roberto B. Corcino2 1 2
Institute of Mathematics, University of the Philippines, Diliman, 1101 Quezon City, Philippines Department of Mathematics, Mindanao State University Main Campus, 9700 Marawi City, Philippines
Correspondence should be addressed to Roberto B. Corcino;
[email protected] Received 5 June 2013; Accepted 1 August 2013 Academic Editor: Zhijun Liu Copyright Β© 2013 C. B. Corcino and R. B. Corcino. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. Asymptotic formulas for the generalized Stirling numbers of the second kind with integer and real parameters are obtained and ranges of validity of the formulas are established. The generalizations of Stirling numbers considered here are generalizations along the line of Hsu and Shuieβs unified generalization.
1. Introduction Asymptotic formulas of the classical Stirling numbers have been done by many authors like Temme [1], Moser, and Wyman [2, 3] due to the importance of the formulas in computing values of the numbers under consideration when parameters become large. The Stirling numbers and their generalization, on the other hand, are important due to their applications in statistics, life science, and physics. The (π, π½)-Stirling numbers [4], the π-Whitney numbers of the second kind [5], and the numbers considered by RuciΒ΄nski and Voigt [6] are exactly the same numbers which can be classified as generalization of the classical Stirling numbers of the second kind. This generalization is in line with the generalization of Hsu and Shuie [7]. For brevity, we can use ππ½,π (π, π) to denote these numbers. These numbers satisfy the following exponential generating function: β π π§π 1 ππ§ π½π§ π) π (π β 1) = π , β (π, π½,π π½π (π!) π! π=π
(1)
where π and π are positive integers. When π½ = 1, (1) reduces to a generating function of π-Stirling numbers [8] of the second kind and further reduces to a generating function of the classical Stirling numbers of the second when π = 0. Combinatorial interpretation and probability distribution involving ππ½,π (π, π) are discussed in [9].
The behavior of the numbers ππ½,π (π, π) was shown to be asymptotically normal in [4, 6]. That means that the distribution of these numbers when the parameters π and π are large will follow a bell-shaped distribution. The unimodality of this distribution was also discussed in [4]. Moreover, the bound for the index in which the maximum value of these numbers occurs has been established in [10]. With these properties of the numbers ππ½,π (π, π), it is necessary to consider the asymptotic formula for the numbers ππ½,π (π, π) to be able to compute large values of the numbers. Applying Cauchy Integral Formula to (1), the following integral representation is obtained: π
ππ½,π (π, π) =
πππ§ (ππ½π§ β 1) π! ππ§, β« 2πππ½π (π!) πΆ π§π+1
(2)
where πΆ is a circle about the origin. The primary purpose of the present paper is to investigate if the analysis in [3] can be extended to the generalized Stirling numbers of the second kind. The authors are motivated by the work of Chelluri et al. [11] which proved the asymptotic equivalence of the formulas obtained by Temme [1] and those obtained by Moser and Wyman in [2, 3]. Moreover, it was also shown in [11] that the formulas obtained apply not only for integral values of the parameters π and π, but for real values as well. To be able to do a similar investigation with that in [11] for the generalized Stirling numbers of the first and second
2
Journal of Applied Mathematics
kinds, it is necessary to come up with asymptotic formulas for each kind generalized Stirling numbers which may have used a method similar to that in [2, 3]. The necessary asymptotic formulas for the generalized Stirling numbers of the first kind can be found in [12, 13]. In this paper, an asymptotic formula for the generalized Stirling numbers of the second kind ππ½,π (π, π) with integral values of π and π are obtained using a similar analysis as that in [3]. The formula is proved to be valid when π > (1/4)ππ and limπ β β (π β π) = β, where π = π/π½. Moreover, other asymptotic formulas are obtained for ππ½,π (π, π), where π and π are real numbers under the conditions π β π β₯ ππΌ and π β π β₯ π1/3 .
2. Preliminary Results ππ€
π
π€
π (π β 1) π! ππ€, β« πβπ 2πππ½ π! πΆ π€π+1
(3)
where π = π/π½, π€ = π½π§. Using the representation π€ = π
πππ , for the circle πΆ, where βπ β€ π β€ π and π
is a positive real number, (3) becomes ππ
ππ
π
ππ
π π π (ππ
π β 1) π! ππ. (4) ππ½,π (π, π) = β« 2ππ½πβπ π
π (π!) βπ ππππ
Multiplying and dividing the right-hand side of (4) by the correction constant π
(ππ
β 1) πππ
,
(5)
it reduces to
π ) β π, 1 β πβπ
π
π
1 π π (π β π
β 1) π»= [ + ], 2 2 π (ππ
β 1)
π·π (π
) =
ππ
1 + Ξπ log (ππ
β 1) , π!π π!
(11) (12) (13)
where Ξ is the operator π
(π/ππ
). Lemma 1. There is a unique 0 < π
< π/π such that π ) β π = 0. 1 β πβπ
(14)
Proof. Equation (14) can be written in the form β1
π
(1 β πβπ
)
=
π π β π
. π π
(15)
Let π1 (π
) = π
(1 β πβπ
)β1 and π2 (π
) = π/π β (π/π)π
. Note that π1 (π
) is a continuous function on (0, β) and limπ
β β π1 (π
) = β while limπ
β 0 π1 (π
) = 1. On the other hand, π2 (π
) is a line with π₯ intercept at π
= π/π and π¦ intercept at π2 (0) = π/π and is decreasing when π and π are positive real numbers. Thus, π1 and π2 , as functions of π
, surely intersect at some point. The value of π
at the intersection point is the desired solution. Moreover, it can be seen graphically that π
< π/π. Lemma 2. π» defined in (12) obeys the inequalities 1 1 π β€π»β€ + . 4 2 2
(16)
Proof. This lemma follows from Lemma 2.2 in [3].
π
ππ½,π (π, π) = π΄ β« exp β (π, π
) ππ,
(6)
βπ
where π΄=
π΅ = π
(π +
π
(π +
The integral representation in (2) can be written in the form ππ½,π (π, π) =
where
π!πππ
(ππ
β 1)
π
2ππ½πβπ π
π π!
,
(7)
Proof. π·π (π
) defined in (13) can be written as
and β(π, π
) is the function, π
πππ
ππ
β (π, π
) = ππ
π + π log (π
π·π (π
) = β 1) (8)
π
β π log (π β 1) β ππ
β πππ. Observe that β(π, π
) can be written in the form β (π, π
) = ππ
πππ β ππ
+ ππ (π, π
) ,
(9)
where π(π, π
) is the same function π(π, π
) which appeared in [14], except for the value of π
. The Maclaurin expansion of β(π, π
) is 2
β
ππ
+ πΆπ (π
) , π!π
(18)
where πΆπ (π
) is the same as that defined in (16) in [3]. Dividing both sides of the preceding equation by π
and taking the absolute value, we have σ΅¨σ΅¨ π· (π
) σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ σ΅¨σ΅¨ πΆ (π
) σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨ π (19) σ΅¨β€ σ΅¨. σ΅¨σ΅¨ σ΅¨σ΅¨ π
σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨ π!π σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨ π
σ΅¨σ΅¨σ΅¨ With π a fixed parameter and π β β as π β β and using Lemma 3.2 in [3], the desired result is obtained. Define π = (ππ
)β3/8 and consider the integral π½ defined by π
π
β (π, π
) = ππ΅π + ππ
π»(ππ) + π β π·π (π
) (ππ) , π=3
Lemma 3. There exists a constant π independent of π and π
such that σ΅¨σ΅¨ π· (π
) σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π (17) σ΅¨σ΅¨ β€ π. σ΅¨σ΅¨ σ΅¨σ΅¨ π
σ΅¨σ΅¨
(10)
π½ = β« exp β (π, π
) ππ. π
(20)
Journal of Applied Mathematics
3
Lemma 4. A constant π > 0 exists such that |π½| β€ π exp (βπ(ππ
)1/4 ) .
The last inequality will yield
Proof. We claim that ππ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ β1 σ΅¨σ΅¨π |β (π, π
)| β€ σ΅¨σ΅¨σ΅¨(ππ
π β 1)σ΅¨σ΅¨σ΅¨ β
σ΅¨σ΅¨σ΅¨(ππ
β 1) σ΅¨σ΅¨σ΅¨ . σ΅¨ σ΅¨ σ΅¨ σ΅¨
(22)
Using the definition of β(π, π
) given by (9), we have σ΅¨ ππ σ΅¨π σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨σ΅¨ ππ
π β 1 σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ βπππ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ ππ σ΅¨ σ΅¨ β
σ΅¨π σ΅¨σ΅¨σ΅¨ . σ΅¨σ΅¨exp β (π, π
)σ΅¨σ΅¨ = σ΅¨σ΅¨exp [ππ
(π β 1)]σ΅¨σ΅¨ β
σ΅¨σ΅¨ π
σ΅¨σ΅¨ π β 1 σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ (23) Because |ππππ | = 1, it remains to show that | exp[ππ
(πππ β 1)]| β€ 1. Note that | exp[ππ
(πππβ1 )]| = πππ
cos π β
πβππ
. The claim now follows from the fact that β1 β€ cos π β€ 1 and ππ
β₯ 0. From (9), β (π, π
) = ππ
(πππ β ππ
) + ππ (π, π
) .
(24)
(25)
The result now follows from the previous claim and the fact that π(π, π
) is the same function π(π, π
) that appeared in [3] except for the value of π
. Observe that when ππ
β β as π β β, Lemma 4 will imply that π½ β 0 as π β β. Indeed, ππ
β β as π β β under some conditions, as shown in the following lemma. Lemma 5. ππ
β β as π β π β β provided π > (1/4)ππ, π > 4. Proof. Write (14) in the form (26)
Now the application of the mean value theorem to the function π(π
) = 1 β πβπ
over the interval (0, π
) will yield 1βπ
provided π β ππ
> 0. The previous inequality can be written in the form ππ ) β₯ π β (π + 4) , (31) ππ
β₯ π β (π β ππ
) β₯ π β (π + π when π β₯ (1/4)ππ. The second inequality previous follows if π
< π/π. Indeed, π
< π/π when π β₯ (1/4)ππ and π > 4 because π1 (π/π) > π2 (π/π), where π1 and π2 are the functions in the proof of Lemma 1. Hence, π
which is the π₯-coordinate of the point of intersection of the two functions must be less than π/π. The last inequality shows that ππ
β β as π β π β β under the given restriction of π. Returning to the condition that π β ππ
> 0, note that π
< π/π. Thus, π π β ππ
> π β π > π β 4, (32) π
For example, when π = 100 and π = 4/7, π in Lemma 5 must satisfy π β₯ (1/4)100(4/7) = 14.2857. Thus, π β₯ 15.
3. Asymptotic Formula with Integral Parameters In the discussion that follows, π
denotes the unique positive solution to (14). It will be seen later that our final asymptotic formula is expressed in terms of powers of 1/ππ
. Anticipating this result and in view of Lemma 4, we write π
ππ½,π (π, π) βΌ π΄ β« exp β (π, π
) ππ.
(33)
βπ
ππ
= π β ππ
. 1 β πβπ
βπ
(30)
under the restriction that π β₯ (1/4)ππ. So that π β ππ
> 0 whenever π > 4.
Thus, σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ ππ σ΅¨σ΅¨exp β (π, π
)σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨σ΅¨exp [ππ
(π β 1)]σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨exp ππ (π, π
)σ΅¨σ΅¨σ΅¨ .
ππ
β₯ (π β ππ
) β π,
(21)
βπ
= π
π ,
(27)
where π is a number within the interval (0, π
). Then, π = πβπ . π β ππ
(28)
Consequently,
Substituting (10) for β(π, π
) and noting that π΅(π
) = 0, (33) becomes π
β
βπ
π=3
ππ½,π (π, π) βΌ π΄ β« exp [βππ
π»π2 + π β π·π (π
) (ππ)π ] ππ. (34) The change of variable π = (ππ
π»)1/2 π will yield ππ = (ππ
π»)1/2 ππ, π=
π (ππ
π»)
1/2
,
ππ =
ππ (ππ
π»)1/2
.
(35)
Now, (34) becomes βπ
1βπ
π = π
( ), π β ππ
π ππ
= πβπ
β€ πβπ = , 1β π β ππ
π β ππ
π ππ
β€ . 1β π β ππ
π β ππ
ππ½,π (π, π) βΌ (29)
πΌ
π΄ (ππ
π»)
where πΌ = (ππ
π»)
1/2
1/2
2
β« πβπ exp [π (π§, π
, π)] ππ, (36) βπΌ
π, π§ = (ππ
π»)β1/2 ,
β
π+2
(ππ) π (π§, π
, π) = β π·π+2 (π
) (ππ
)βπ/2 . (π+2)/2 π
π» π=1
(37)
4
Journal of Applied Mathematics The equation in (37) can be written in the from
It can be computed that
β
π (π§, π
, π) = β ππ π§π ,
(38)
π0 = 1,
π=1
β«
where
2
ββ
π+2
(ππ) . π
π»(π+2)/2
ππ = π·π+2 (π
)
β
πβπ ππ = βπ,
1 2 π2 = π2 (π
, π) + [π1 (π
, π)] , 2
(39)
4
Note here that π§ = (ππ
)β1/2 is within the radius of convergence of the series in (38). On the other hand, the Maclaurin series of exp π(π§, π
, π) is
π2 = π·4 (π
) π·4 (π
) =
β
ππ(π§,π
,π) = β ππ (π
, π) π§π ,
(48)
(40)
(ππ) , π
π»2
ππ
+ πΆ4 (π
) , 24π
π=0
where π2π is a polynomial in π containing only even powers of π, and π2π+1 is a polynomial in π containing only odd powers of π. Now, (36) can be written in the form πΌ
where πΆ4 (π
) =
β
2
ππ½,π (π, π) βΌ π β« πβπ ( β ππ (π
, π) π§π ) ππ, βπΌ
(41)
+
π=0
where π = π΄/βππ
π» and π§ = (ππ
) We write (41) as π β1
πΌ
π=0
βπΌ
β1/2
β1 1 [π
+ (π
β 7π
2 + 6π
3 β π
4 ) (ππ
β 1) ] 24 β2 1 [(18π
3 β 7π
2 β 7π
4 ) (ππ
β 1) 24 3
4
π
β3
(49)
+ (12π
β 12π
) (π β 1) ]
.
2
ππ½,π (π, π) βΌ π [ β π§π (β« πβπ ππ ππ) + ππ ] ,
β (42)
β4 1 [6π
4 (ππ
β 1) ] , 24
while
where β
πΌ
2
ππ = β (β« πβπ ππ ππ) π§π . βπΌ
π=π
In view of Lemma 2, π» β₯ 1/4; hence, 1/2
πΌ = (ππ
π»)
1/2
π = (ππ
π»)
β3/8
(ππ
)
3
(ππ
)1/8 β₯ . 2
β
π=0
β
ββ
2
πβπ π2π ππ) (ππ
)βπ ] .
(50)
where (44) πΆ3 =
Since ππ is a polynomial in π, we can replace πΌ with β in (41). Following the discussion in [3], it can be shown that ππ = π(π§π ); hence, we have the asymptotic formula ππ½,π (π, π) βΌ π [ β (β«
3
(ππ) (ππ) ππ
π1 (π
, π) = π·3 =( , + πΆ3 ) 3!π π
π»3/2 π
π»3/2
(43)
β1 1 [π
+ (π
β 3π
2 + π
3 ) (ππ
β 1) 6 β2
+ (3π
3 β 3π
2 ) (ππ
β 1) ] +
(45)
(51)
β3 1 [2π
3 (ππ
β 1) ] . 6
Thus, π2 can be written as follows:
Note that β
β«
ββ
2
πβπ π2π+1 ππ = 0.
(46)
This is why no odd subscript of ππ appears in (45). An approximation is obtained by taking the first two terms of the sum in (45). Thus, ππ½,π (π, π) β π [β«
β
ββ
2
πβπ π0 ππ + (ππ
)β1 β«
β
ββ
π2 = [
2 ππ
π4 π6 1 ππ
β ) . + πΆ4 ] ( + πΆ 3 24π π
π»2 2 6π π
2 π»3
(52)
Let
2
πβπ π2 ππ] . (47)
πΌ=β«
β
ββ
2
πβπ π2 ππ.
(53)
Journal of Applied Mathematics
5 Table 1
Then, πΌ=β«
β
ββ
2
πβπ
(ππ
/24π + πΆ4 ) 4 π ππ π
π»2 2
β =
1 β βπ2 (ππ
/6π + πΆ3 ) 6 π ππ β« π 2 ββ π
2 π»3
ππ
/24π + πΆ4 β βπ2 4 β« π π ππ π
π»2 ββ
(54)
Exact value 5.685 Γ 10152 7.728 Γ 10171 8.411 Γ 10178 5.604 Γ 10174 7.399 Γ 10122 1.275 Γ 1070 2.208 Γ 1038
π7,4 (100, 5) π7,4 (100, 10) π7,4 (100, 15) π7,4 (100, 30) π7,4 (100, 60) π7,4 (100, 80) π7,4 (100, 90)
Approximate value 6.335 Γ 10152 8.169 Γ 10171 8.731 Γ 10178 5.706 Γ 10174 7.446 Γ 10122 1.279 Γ 1070 2.211 Γ 1038
Relative error 0.11428 0.05713 0.03804 0.01824 0.00641 0.00263 0.00123
2
β
(ππ
/6π + πΆ3 ) β βπ2 6 β« π π ππ 2π
2 π»3 ββ
Note that by change of variable, say π€ = π½π§, we can express ππ½,π (π₯, π¦) as follows:
2
=
ππ
/24π + πΆ4 3βπ (ππ
/6π + πΆ3 ) 15βπ β
β
β . π
π»2 4 π
2 π»3 16
π π₯+ } { { { } π½} ππ½,π (π₯, π¦) = π½π₯βπ¦ { } , π { {π¦ + } } π½ }π/π½ {
Finally, we obtain the approximation formula π
ππ
π
πΌ π! π (π β 1) [1 + ]. ππ½,π (π, π) β π! 2π½πβπ π
π βπππ
π» ππ
βπ
(55)
In view of Lemmas 4 and 5 and (33), the previous asymptotic approximation is valid for π β₯ (1/4)ππ. The formula obtained in the previous discussion is formally stated in the following theorem. Theorem 6. The formula ππ½,π (π, π) βΌ π [βπ +
πΌ ] ππ
(56)
behaves as an asymptotic approximation for the generalized Stirling numbers of the second kind ππ½,π (π, π) with positive integral parameters for π > (1/4)ππ, π > 4 and such that π β π β β as π β β. Table 1 displays the exact values and approximate values for π = 100, π = 4, π½ = 7. The exact values are obtained using recurrence formula while the approximate values are obtained using Theorem 6. In view of Lemma 5, the formula is valid for π β₯ 15. Values on the table affirm that the asymptotic formula in Theorem 6 gives a good approximation for π7,4 (100, π) when π β₯ 15.
4. Asymptotic Formula with Real Parameters Recently, the (π, π½)-Stirling numbers for complex arguments were defined in [15] parallel to the definition of Flajolet and Prodinger as ππ½,π (π₯, π¦) =
π¦ ππ§ π₯! β« πππ§ (ππ½π§ β 1) π₯+1 , π¦!π½π¦ 2ππ H π§
(57)
where π₯! := Ξ(π₯ + 1) and H is a Hankel contour that starts from ββ below the negative axis surrounds the origin counterclockwise and returns to ββ in the half plane Iπ§ > 0.
(58)
where {
π₯! π₯+π π¦ ππ§ } = β« πππ§ (ππ§ β 1) π₯+1 . π¦ + π π π¦!2ππ H π§
(59)
π₯+π The numbers { π¦+π }π are certain generalization of πStirling numbers of the second kind [8] in which the parameters involved are complex numbers. These numbers satisfy the following properties.
Theorem 7. For nonnegative real number π, one has {
π₯+πβ1 π₯+πβ1 π₯+π } + (π¦ + π) { }. } ={ π¦+πβ1 π π¦+π π π¦+π π
(60)
Theorem 8. For nonnegative real numbers π and π½ and π β N, one has 1 π π₯+π π π₯ { } = β (β1)πβπ ( ) (π + π) . π + π π π! π π=0
(61)
Furthermore, when π = π¦, a complex number 1 β π₯+π π¦ π₯ { } = β (β1)π¦βπ ( ) (π + π) . π¦ + π π π¦! π π=0
(62)
The Bernoulli polynomial can be expressed using the explicit formula in [16] and the first formula in Theorem 8, with π€ = π and π₯ = π, as β
(β1)π π! π + π { }. π+1 π+π π π=0
π΅π (π) = β
(63)
Moreover, it is known that, for π = 1, 2, . . ., the Hurwitz zeta function π(1 β π, π₯) = βπ΅π (π₯)/π. Note that, as π¦ β 0, (π¦ β 1)! βΌ 1/π¦. By Cauchyβs integral formula π΅ (π) πππ§ π+π { = π¦ π+1 , } βΌ π¦π! [π§π+1 ] π§ π¦+πβ1 π π β1 π+1
(64)
6
Journal of Applied Mathematics
which further gives, using a result in [17], the following relation: [
π π+π = βπ (βπ, π) { }] ππ¦ π¦ + π π π¦=β1 =
π! β1 ππ§ β« πππ§ (ππ§ β 1) π+1 . 2ππ H π§
where β«πΆ |ππ§| is the length of πΆ1 . With πΆ1 the horizontal line 1 Iπ§ = β2π + πΏ, the length of πΆ1 is a linear function of the real part of π§, given by π (πΆ1 ) = lim (π β π‘) .
(71)
π‘ββ
(65) Hence, we have
An asymptotic formula for π-Stirling numbers of the second kind was first considered by Corcino et al. in [14]. However, the formula only holds for integral arguments. In this section, we are going to establish an asymptotic formula for π-Stirling numbers of the second kind that will hold for real arguments. Consider the integral representation in (59) where |Iπ§| < 2π. To see the analysis of Moser-Wyman applies to π-Stirling numbers with real arguments π₯ and π¦, we deform the path H into the following contour: πΆ1 βͺ πΆ2 βͺ πΆ3 βͺ πΆ4 βͺ πΆ5 where
π¦ σ΅¨σ΅¨ σ΅¨σ΅¨ (ππ§ β 1) σ΅¨σ΅¨ σ΅¨σ΅¨ (2 + π)π¦ σ΅¨σ΅¨β« σ΅¨σ΅¨ β€ ππ§ lim (π β π‘) π₯+1 σ΅¨σ΅¨ πΆ σ΅¨ σ΅¨σ΅¨ (2π β πΏ)π₯+1 π‘ β β σ΅¨ 1 π§
limπ‘ β β (π β π‘) < . (2π β πΏ)π₯βπ¦
(72)
The last inequality follows from the fact that 2+π < 2πβπΏ. With the condition that π₯ β π¦ β₯ π₯πΌ , 0 < πΌ < 1, and the fact that 2π β πΏ > π, it follows that the integral along πΆ1 goes to 0 as π₯ β β. Thus, we have π¦
(1) πΆ1 is the line Iπ§ = β2π + πΏ, πΏ > 0 and Rπ§ β€ π, π is a small positive number;
πππ§ (ππ§ β 1) π₯! 1 π₯+π ππ§. { } βΌ β« π¦ + π π π¦! 2ππ πΆ3 π§π₯+1
(2) πΆ2 is the line segment Rπ§ = π, going from π+π(πΏβ2π) to the circle |π§| = π
;
Using the method of Moser and Wyman [3], we obtain the following asymptotic formula.
(3) πΆ5 and πΆ4 are the reflections in the real axis of πΆ1 and πΆ2 , respectively; and (4) πΆ3 is the portion of the circle |π§| = π
, meeting πΆ2 and πΆ4 .
(73)
Theorem 9. The π-Stirling numbers of the second kind with real arguments π₯ and π¦ have the following asymptotic formula: π¦
ππ
π
π₯! π (π β 1) 1 π₯+π [1 + π ( )] { } = π¦ + π π π¦! 2π
π₯ βππ¦π
π» π¦
(74)
The new contour is πΆ1 βͺ πΆ2 βͺ πΆ3 βͺ πΆ4 βͺ πΆ5 in the counterclockwise sense. This idea of deforming the contour H is also done in [11]. The integrals along πΆ1 , πΆ2 , πΆ4 , and πΆ5 are seen to be
valid for π₯ β π¦ β β as π₯ β β, provided that π₯ β π¦ β₯ π₯πΌ with 0 < πΌ < 1, where
(2 + π)π¦ π( ). (2π β πΏ)π₯
ππ
(ππ
β π
β 1) π π»= , + 2 2π¦ 2(ππ
β 1)
(66)
It will also be shown that these integrals go to 0 as π₯ β β provided that π₯ β π¦ β₯ π₯πΌ where 0 < πΌ < 1. To see this, we consider πΆ1 . For the other contours, the estimate can be seen similarly. Note that for π§ in πΆ1 , we can choose πΏ so that β1 2
[1 β (πRπ§ cos (Iπ§)) ] < 1.
(67)
From this and the assumptions that Rπ§ < π and π < 1, it follows that 2+π σ΅¨σ΅¨ π§ σ΅¨ Rπ§ < 2 + π. σ΅¨σ΅¨π β 1σ΅¨σ΅¨σ΅¨ β€ π < π < 2βπ
(68)
β1
π€ [π β π¦(1 β πβπ€ ) ] β π₯ = 0,
(76)
as a function of π€. Chelluri et al. [11] has made a modification of Moser and Wyman formula and analysis. Using this analysis of Chelluri, we can restate Theorem 9 as follows. Theorem 10. The π-Stirling numbers of the second kind with real arguments π₯ and π¦ have the following asymptotic formula: π¦
(69)
Consequently, π¦ σ΅¨σ΅¨ σ΅¨σ΅¨ (ππ§ β 1) σ΅¨σ΅¨ σ΅¨σ΅¨ (2 + π)π¦ σ΅¨ σ΅¨σ΅¨β« β€ , ππ§ β« σ΅¨σ΅¨ π₯+1 |ππ§| π₯+1 σ΅¨σ΅¨ πΆ σ΅¨σ΅¨ πΆ1 (2π β πΏ) σ΅¨ 1 π§
and π
is the unique positive solution to the equation
ππ
π
π₯! π (π β 1) 1 π₯+π [1 + π ( )] { } = π¦ + π π π¦! 2π
π₯ βππ¦π
π» π₯
Thus, σ΅¨σ΅¨ π§ σ΅¨π¦ π¦ σ΅¨σ΅¨π β 1σ΅¨σ΅¨σ΅¨ < (2 + π) .
(75)
(70)
(77)
valid for π₯ β π¦ β β as π₯ β β, provided that π₯ β π¦ β₯ π₯1/3 , where ππ
(ππ
β π
β 1) π π»= , + 2 2π¦ 2(ππ
β 1)
(78)
Journal of Applied Mathematics
7
and π
is the unique positive solution to the equation β1
π€ [π β π¦(1 β πβπ€ ) ] β π₯ = 0,
(79)
as a function of π€. As noted in (58), the (π, π½)-Stirling numbers can be obtained using the π-Stirling numbers of the second kind for complex arguments π₯, π¦, π, and π½. This implies, using Theorems 9 and 10, the following asymptotic formulas which agree with the formula in (55) for the integral values of π₯ and π¦. Corollary 11. The (π, π½)-Stirling numbers with real arguments π₯ and π¦ have the following asymptotic formulas: π¦
ππ
/π½ π
π½π₯βπ¦ π₯! π (π β 1) 1 [1 + π ( )] ππ½,π (π₯, π¦) = π¦! π¦ 2π
π₯ βππ¦π
π»
(80)
provided that π₯ β π¦ β₯ π₯πΌ with 0 < πΌ < 1, and π¦
ππ
/π½ π
π½π₯βπ¦ π₯! π (π β 1) 1 ππ½,π (π₯, π¦) = [1 + π ( )] π₯ π¦! π₯ 2π
βππ¦π
π»
(81)
provided that π₯ β π¦ β₯ π₯1/3 , where π»=
ππ
(ππ
β π
β 1) π + 2 2π½π¦ 2(ππ
β 1)
(82)
and π
is the unique positive solution to the equation π€[
π β1 β π¦(1 β πβπ€ ) ] β π₯ = 0 π½
(83)
as a function of π€.
Acknowledgment The authors would like to thank the referee for reading and evaluating the paper.
References [1] N. M. Temme, βAsymptotic estimates of Stirling numbers,β Studies in Applied Mathematics, vol. 89, no. 3, pp. 233β243, 1993. [2] L. Moser and M. Wyman, βAsymptotic development of the Stirling numbers of the first kind,β Journal of the London Mathematical Society, vol. 33, pp. 133β146, 1958. [3] L. Moser and M. Wyman, βStirling numbers of the second kind,β Duke Mathematical Journal, vol. 25, pp. 29β43, 1957. [4] R. B. Corcino, C. B. Corcino, and R. Aldema, βAsymptotic normality of the (π, π½)-Stirling numbers,β Ars Combinatoria, vol. 81, pp. 81β96, 2006. [5] I. MezΛo, βA new formula for the Bernoulli polynomials,β Results in Mathematics, vol. 58, no. 3-4, pp. 329β335, 2010. [6] A. RuciΒ΄nski and B. Voigt, βA local limit theorem for generalized Stirling numbers,β Revue Roumaine de MathΒ΄ematiques Pures et AppliquΒ΄ees, vol. 35, no. 2, pp. 161β172, 1990.
[7] L. C. Hsu and P. J. S. Shuie, βA unified approach to generalized stirling numbers,β Advances in Applied Mathematics, vol. 20, no. 3, pp. 366β384, 1998. [8] A. Z. Broder, βThe π-stirling numbers,β Discrete Mathematics, vol. 49, no. 3, pp. 241β259, 1984. [9] R. B. Corcino and R. Aldema, βSome combinatorial and statistical applications of (π, π½)-Stirling numbers,β MatimyΒ΄as Matematika, vol. 25, no. 1, pp. 19β29, 2002. [10] R. B. Corcino and C. B. Corcino, βOn the maximum of generalized Stirling numbers,β Utilitas Mathematica, vol. 86, pp. 241β256, 2011. [11] R. Chelluri, L. B. Richmond, and N. M. Temme, βAsymptotic estimates for generalized Stirling numbers,β Analysis, vol. 20, no. 1, pp. 1β13, 2000. [12] M. A. R. P. Vega and C. B. Corcino, βAn asymptotic formula for the generalized Stirling numbers of the first kind,β Utilitas Mathematica, vol. 73, pp. 129β141, 2007. [13] M. A. R. P. Vega and C. B. Corcino, βMore asymptotic formulas for the generalized Stirling numbers of the first kind,β Utilitas Mathematica, vol. 75, pp. 259β272, 2008. [14] C. B. Corcino, L. C. Hsu, and E. L. Tan, βAsymptotic approximations of π-stirling numbers,β Approximation Theory and Its Applications, vol. 15, no. 3, pp. 13β25, 1999. [15] R. B. Corcino, C. B. Corcino, and M. B. Montero, βOn generalized Bell numbers for complex argument,β Utilitas Mathematica, vol. 88, pp. 267β279, 2012. [16] F. W. J. Olver, D. Lozier, R. F. Boisvert, and C. W. Clark, NIST Handbook of Mathematical Functions, Cambridge University Press, Washington, DC, USA, 2010. [17] K. N. Boyadzhiev, βEvaluation of series with Hurwitz and Lerch zeta function coefficients by using Hankel contour integrals,β Applied Mathematics and Computation, vol. 186, no. 2, pp. 1559β 1571, 2007.
Advances in
Operations Research Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Advances in
Decision Sciences Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Journal of
Applied Mathematics
Algebra
Hindawi Publishing Corporation http://www.hindawi.com
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Journal of
Probability and Statistics Volume 2014
The Scientific World Journal Hindawi Publishing Corporation http://www.hindawi.com
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
International Journal of
Differential Equations Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Volume 2014
Submit your manuscripts at http://www.hindawi.com International Journal of
Advances in
Combinatorics Hindawi Publishing Corporation http://www.hindawi.com
Mathematical Physics Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Journal of
Complex Analysis Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
International Journal of Mathematics and Mathematical Sciences
Mathematical Problems in Engineering
Journal of
Mathematics Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Volume 2014
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Discrete Mathematics
Journal of
Volume 2014
Hindawi Publishing Corporation http://www.hindawi.com
Discrete Dynamics in Nature and Society
Journal of
Function Spaces Hindawi Publishing Corporation http://www.hindawi.com
Abstract and Applied Analysis
Volume 2014
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
International Journal of
Journal of
Stochastic Analysis
Optimization
Hindawi Publishing Corporation http://www.hindawi.com
Hindawi Publishing Corporation http://www.hindawi.com
Volume 2014
Volume 2014