Giancoli Ch 15-23 Transverse wave on a string. Set up parameters with the given
information. v .2 m sec. D0x ..0.45 m cos . .3 m 1 x. 1.2 x .. ,.0 m ..1 m .2π .3 m 1.
Giancoli Ch 15-23 Transverse wave on a string Set up parameters with the given information. 2.
v
m sec
0.45 . m . cos 3 . m 1 . x 2.π 0 . m , .1 . m .. 3.m 1
D0 x x
1.2
0.5
D0 x
0
0.5 0
1 x
2
The general formula for a wave is: D x, t k 2.
D M . cos k . x
π λ
ω.t
φ
ω 2.π .f
v λ.f Examining the formula we can see k=3m -1 and this gives us λ. Since we know v we can also get f and ω. k
3.m 1
λ
2.
f
v λ
π k
λ = 2.094 m
f = 0.955 Hz ω
2. π .f
φ
1.2
DM
0.35 . m Giancoli 15-23.mcd-1
02/13/02
D M . cos k . x
D right x , t
ω. t
φ
0.5
D right x , 1. sec
0
0.5 0
1 x
2
(d) For left going wave, everything is the same except a plus sign replaces the minus sign in the formula. D left x , t
