Problems calculating mass defect - ChemConnections

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Problems%20calculating%20mass%20def... Problems calculating mass defect. PART 1: What is the mass defect for 3Li6, the lithium isotope with 3 neutrons and  ...
http://www.chem.missouri.edu/.../Problems%20calculating%20mass%20def... Problems calculating mass defect PART 1: What is the mass defect for 3Li6, the lithium isotope with 3 neutrons and an atomic weight of 6.01513?

2. Calculate the mass defect for 17Cl35 whose mass is 34.9689 AMU.

3. The actual mass of 29Cu63 is 62.9298 AMU. What is its mass defect?

4. The actual mass of 35Br81 is 80.9163 AMU. What is its mass defect?

5. The actual mass of 52Te120 is 119.9045 AMU. What is its mass defect?

PART 2: Calculate the energy in 1 mole of the materials from the mass defect.

ANSWERS answers with solutions mass of mass of calc mass act mass of mass isotope mass of neutrons protons electrons of atom atom defect 3 * 1.0073 3 * 1.0087= 3 * .00055 6 6.0497 6.01513 .0346 3Li = 3.0219 3.0261 = .0017 17 * 1.0073 18 * 17 * .00055 35 35.290 34.9689 .321 17Cl = 17.124 1.0087=18.157 = .0093 29 * 1.0073 34 * 1.0087= 29 * .00055 63 63.523 62.9298 .594 29Cu = 29.212 34.296 = .016 35 * 1.0073 46 * 1.0087= 35 * .00055 81 81.675 80.9163 .759 35Br = 35.256 46.400 = .019 52 * 1.0073 68 * 52 * .00055 120 121.001 119.9045 1.096 52Te = 52.380 1.0087=68.592 = .029 answers with solutions .0345 AMU* 6.02E23 atoms * [1g/6.023E23AMU] [3.00E8m/s]2*[1kg/1000g] = 1 3.11E12 kg m2/s2 = 3.11E12 J .321 AMU* 6.02E23 atoms * [1g/6.023E23AMU] [3.00E8m/s]2*[1kg/1000g] = 2 2.89E13 kg m2/s2 = 2.89E13 J .594AMU* 6.02E23 atoms * [1g/6.023E23AMU] [3.00E8m/s]2*[1kg/1000g] = 5.35E13 3 kg m2/s2 = 5.35E13 J .759AMU* 6.02E23 atoms * [1g/6.023E23AMU] [3.00E8m/s]2*[1kg/1000g] = 6.84E13 4 kg m2/s2 = 6.84E13 J 1.095AMU* 6.02E23 atoms * [1g/6.023E23AMU] [3.00E8m/s]2*[1kg/1000g] = 5 9.87E13 kg m2/s2 = 9.87E13 J